Ls 2 - Electrostatic Potential and Capacitance
Notes
Questions
A regular hexagon of side 10cm has a charge 5uC at each of its vertices . Calculate the potential at the centre of the hexagon.
As in the figure, if a capacitor of capacitance 'C' is charged by connecting it with resistance 'R', then energy given by the battery will be a) 1/2CV^2 b) less than 1/2CV^2 c) CV^2 d) more than CV^2
There is a uniform electrostatic field in a region. The potential at various points on a small sphere centred at P, in the region, is found to vary between in the limits 589.0 V to 589.8 V. What is the potential at a point on the sphere whose radius vector makes an angle of 60 deg with the direction of the field? (A) 589.5 V (B) 589.2 V (C) 589.4 V (D) 589.6 V
Worksheet
Notes
Formula Cheat sheet

Electric potential:
W =
E = (relation between electric intensity and potential)
Electric potential at point due to isolated point charge,
Electric potential at point due to an electric dipole,
Potential energy of system of charges in the absence of external electric field - is due to superposition principle which is very similar to addition of vectors
Potential energy of system of charges in the presence of external electric field
Single charge: - U = Vq
Two charges: -
Electric dipole:
Capacitance of parallel plate capacitor:
Energy stored in capacitor,
Series combination of capacitors, -= +1+- C1C2
For two capacitors connected in series, Cs = +C2
For n identical capacitors connected in series, Cn =-
Parallel combination of capacitors, = C1 + C2+ C3
For two Capacitors connected in parallel, = C1+ C2
For n identical capacitors connected in parallel, = nC
Dielectric polarization P = x E where x is electric susceptibility
Last updated
Was this helpful?